QuizSolver
  • Bank PO
  • CBSE
  • IIT JEE
 
 

Basic Theory on SYMBOLS AND NOTATIONS for Upcoming Bank PO and SSC Exam

Posted on - 27-04-2017

Reasoning SYMBOLS AND NOTATIONS

Bank PO

The basic approach for the questions of this chapter is more or less similar to that of coding and decoding. As in the questions of coding and decoding, a basic word is coded in a particular way and the candidate is asked to code another word using the same logic.

Similarly in "Symbols and Notations", one lias to study the symbols and their meanings carefully which are given against them. Then, the meanings given are to be used in place of those symbols in answering the questions. The word "Notation" basically stands for the meaning which each symbol will be assigned.

The questions can be based on Blood Relations or Mathematical Operations (or Operator based questions). This chapter deals with Mathematical Operations.

Mathematical Operations :

Symbols for these types of questions stand for mathematical operations i.e. +, – , x, ÷, >, <, >, <, = and #. So one must replace the symbols by mathematical operations and apply the 'BODMAS' rule to find the value of the given expression. Symbols like , , *, @, $ etc are used by giving a proper definition of the symbol used. An example belonging to this category is also explained below.

Worked out Examples :

Example 1.   

If' – ' stands for 'x', 'x' stands for '+','+' stands for '÷' and '÷' stands for ' – ', then what is the value of 9 ÷ 18 x 15 + 3 – 6 × 12?

(a) 24

(b) 30

(c) 33

(d) 42

Solution.

The given expression is 9 ÷ 18 × 15 + 3 – 6 × 12. By converting the symbols according to the given definitions, we get 9 – 18 + 15 ÷ 3 × 6 + 12. Solving this by BODMAS rule, we get the value as 33. .

Choice (c)

Example 2.   

If a $ b = a2b2 – ab, then 3 $ 8 =

(a) 600

(b) 552

(c) 576

(d)625

Solution.    

Given a $ b = a2b2 – ab.

3$8 = 32x82 – 3 x 8 = 9 x 64 – 24

= 576 – 24 = 552.

Choice (b)

Example 3.   

If p q = p2 + q2 – p – q and p q = pq – p – q, then (6 5) 5 =

(a) 200

(b) 175

(c) 195

(d) 179

Solution.

65 = 62 + 52 – 6 – 5 = 36+ 25 – 6 – 5 = 50

(65) 5 = 505 = 50x5 – 50 – 5 = 195.

Choice (c)

Example 4.   

If 4 O 5 = 189 and 10 O 8= 1512, then 6 O 9 =

(a) 945

(b) 1148

(c) 983

(d) 764

Solution.    

43 + 53 = 64+125=189405

103 + 83 = 1000 + 512 = 1512 10 O 8

Similarly, 6 O 9 = 63 + 93 = 216 + 729 = 945. Choice (a).

Example 5.   

If '' means 'is less than', '$' means 'is greater than' and '£' means 'is equal to' and given that a b, c £ d and c $ b, then which of the following is true?

(a) d a

(b) b $ d

(c) a £ c

(d) a b c

Solution.

a b a < b

c $ b c > b b < c

c £ d c = d

a < b < c = d

(a) d a d < a false

(b) b $ db > d false

(c) a £ ca = cfalse

(d) a b ca < b< c true

Choice (d)

 
Practice Questions 3 on EQUATIONS for Bank PO And SSC
Practice Questions 2 on EQUATIONS for Bank PO And SSC
Basics of VARIATION for Banking and SSC
Basics of RATIO for Banking and SSC
Some important Question on PERCENTAGE for upcoming Bank Exams
Practice Questions on Equations for upcoming Bank PO and SSC
Basics of Equations in One Two and Three Variables for Bank PO and SSC
How To Solve Blood Relation Questions Easily for Bank PO and SSC Exams
How To Solve Profit and Loss Questions for Bank PO and SSC Exams
How to Solve Time and Work Questions for the Upcoming Bank PO and SSC Exams
Basic Theory for BLOOD RELATIONS for Bank PO and SSC Exams
Tips and Tricks for PARTNERSHIP for Bank PO and SSC
Miscellaneous Series
Squares and Cubes Series
Number Analogies for Bank PO and SSC
Type of Series - Product Series
Type of Series - Difference Series
About Number and Letter Series for Banking and SSC Exams
Letter Series Type 2 for Banking and SSC
Basics of PROPORTION for Bank PO

Comments